A particle is executing simple harmonic motion (SHM) of amplitude A, along the x-axis, about x = 0. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be:
A
B
C
A
D
Text Solution
Verified by ExpertsThe correct answer is:
D
K.E. = P.E.
K(A 2 – x 2 ) = 
kx 2
A 2 – x 2 = x 2
x = ± 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A mass M, attached to a horizontal spring, executes SHM with a amplitude A 1 . When the mass M pass…
Two particles are executing simple harmonic motion of the same amplitude A and frequency ꞷ along th…
If a simple pendulum has significant amplitude (up to a factor of 1/e of original) only in the peri…
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude is 5s. In anothe…
A particle moves with simple harmonic motion in a straight line. In first τ s, after starting from …
For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE)…